A) NaOH + AI(OH)3 + HCI = Na[AI(OH)4] + NaCI + H20
B) NaOH + AI(OH)3 + H2S04 = NaAI(S04)2H20
C) NaOH + Af(OH)3 + H2C03 = Al203 + NaHC03 + 4H20
D) 4NaOH + AI(OH)3 + 6HF = Na3AIF6 + 6H20
A) NaOH + AI(OH)3 + HCI = Na[AI(OH)4] + NaCI + H20
B) NaOH + AI(OH)3 + H2S04 = NaAI(S04)2H20
C) NaOH + Af(OH)3 + H2C03 = Al203 + NaHC03 + 4H20
D) 4NaOH + AI(OH)3 + 6HF = Na3AIF6 + 6H20
Ответ: |
Сборник: Kimyo
Параграф:
65. Alyuminiy
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