A) 2CH4 -> CH3-CH3 + H2
B) CH3-CH2-OH + CH2COOH CH3-CH2-0-C02C0 + 2H20
C) CH3COOH + 203 -> 2C02 + 2H20
D) C6H6 + HN03 -> C6H5N02 + H20
E) C6H5N02 + 3H2 -> C6H5NH2. + 2H20
A) 2CH4 -> CH3-CH3 + H2
B) CH3-CH2-OH + CH2COOH CH3-CH2-0-C02C0 + 2H20
C) CH3COOH + 203 -> 2C02 + 2H20
D) C6H6 + HN03 -> C6H5N02 + H20
E) C6H5N02 + 3H2 -> C6H5NH2. + 2H20
Ответ: |
Сборник: Kimyo
Параграф:
87.7. Eterifikatsiya reaksiyalari
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