KMn04 + NaCI + I H2S04 = Cl2 + K2S04 + MnS04 + Na^O,* + H20 i Ushbu ok

A) 2

121. (V20/21 -125-11) KMn04 + NaCI + I H2S04 = Cl2 + K2S04 + MnS04 + Na^O,* + H20 i Ushbu oksidlanish-qaytarilish reaksiyasida i 1 mol xlor molekulasiga necha mol I oksidlovchi molekulasi togri keladi? A) 2 B) 0,4 C)2,5
D) 5