109. (v13-103-2) 115 g bir atomli toyingan spirt molekulasida 22,5 mol atom bolsa, nomalum spirtni toping.
A) C4H9OH Р’) C5H11OH
C) C3H7OH
D) C2H5OH
109. (v13-103-2) 115 g bir atomli toyingan spirt molekulasida 22,5 mol atom bolsa, nomalum spirtni toping.
A) C4H9OH Р’) C5H11OH
C) C3H7OH
D) C2H5OH
Ответ: |
Сборник: Kimyo
Параграф:
95.1. Organik moddalarning formulasini chiqarish bo‘yicha masalalar
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